Python 2811.py
class Solution:
def canSplitArray(self, nums: List[int], m: int) -> bool:
# if there are two values a and b, that are located next to each other, and a + b >= m
# then we can continuously chop off a single value on the left or right end of the array
# and finally split a and b
return len(nums) <= 2 or any(a + b >= m for a, b in zip(nums, nums[1 :]))
Difficulty
and has an acceptance rate of about 35% (90k+ submissions).
Typical patterns to solve this problem:
- Array
- Dynamic Programming
- Greedy
AI Disclaimer
However, two years later I set up this website and used various AI tools to generate most of the walkthrough / explanations below.
See this dedicated page for more details.
Code Walkthrough
Overview
The provided Solution class implements a single method canSplitArray. The method receives a list of integers nums and an integer threshold m. Its purpose is to determine whether the array can be reduced, by repeatedly removing elements from either end, until only two adjacent elements remain whose sum meets or exceeds the threshold m. The implementation returns a Boolean value indicating the feasibility of such a reduction.
Key Steps
The first logical step checks the size of the input array. If the array contains two or fewer elements, the method immediately returns True. This reflects the fact that no chopping is required when the array is already at the minimal size needed for the final condition.
if len(nums) <= 2:
return True
When the array is larger, the method proceeds to evaluate every pair of consecutive elements. It uses the built-in any function together with a generator expression that iterates over the zipped view of the list and its tail. For each adjacent pair (a, b), it computes the sum a + b and checks whether this sum is at least m. The any function short-circuits as soon as it encounters a pair satisfying the condition, returning True; otherwise it exhausts the iterator and returns False.
return any(a + b >= m for a, b in zip(nums, nums[1:]))
The combination of the early size check and the generator expression constitutes the entire decision logic of the method.
Edge Cases Handled
The early size check implicitly covers several edge scenarios. An empty list (nums = []) has a length of zero, which satisfies the len(nums) <= 2 condition, leading the method to return True. This aligns with the interpretation that no elements need to be removed and the final condition is vacuously satisfied. A single-element list (nums = [x]) also triggers the same branch, returning True because there are no adjacent pairs to evaluate, and the problem definition permits immediate success when the array size is already at or below two.
When the list contains exactly two elements, the method again returns True without examining their sum. This reflects the specification that the final split can be performed as long as the array size is two, regardless of whether the sum meets the threshold. The subsequent any expression is therefore never executed for arrays of size two or less, avoiding unnecessary computation.
For arrays longer than two elements, the generator expression gracefully handles the situation where no adjacent pair reaches the threshold. In that case, any evaluates the entire sequence of pairs and ultimately yields False, indicating that no sequence of end-chops can produce a qualifying final pair.
Performance Optimizations
The implementation leverages short-circuit evaluation in two distinct ways. First, the size check len(nums) <= 2 provides an immediate answer for small inputs, bypassing any iteration. This eliminates overhead for trivial cases and prevents the creation of intermediate iterators.
Second, the use of a generator expression inside any ensures that pairs are generated lazily. The zip function pairs each element with its immediate successor without constructing a full list of tuples. As soon as a qualifying pair is found, any stops further iteration, avoiding unnecessary sum calculations for the remainder of the array. This on-the-fly evaluation reduces both memory footprint and processing time for typical inputs where a qualifying pair appears early in the sequence.
The overall flow avoids explicit loops, conditional branches inside the loop, or auxiliary data structures, resulting in a compact and efficient execution path that directly maps the problem statement to Python’s high-level constructs.
ELI5 - Simplified Explanation
Imagine you have a long row of building blocks sitting on the floor. The goal is to break this row into smaller pieces until every piece is just a single block by itself.
The code looks at the blocks to see if there is any place where two neighbors are strong enough to help with this task. When two blocks side by side add up to a big enough number, they act like a magic key. This key allows the row to be broken down one by one until only single blocks remain. If the row is already very tiny with only one or two blocks, it is already simple to manage. If there is at least one pair of best friends sitting next to each other who are strong enough, the whole row can be taken apart piece by piece.
Code Quality
Complexity Analysis
As a rule of thumb, the maximum input size for one second execution time is
- factorial: up to 10 elements
- exponential: up to 20 elements
- polynomial: a few thousand elements
- loglinear: up to 100,000 elements
- linear: a few million elements
- logarithmic: a billion elements
- constant: practically unlimited
Other Solutions
Obviously, I did that after I solved the problem myself.
In general, AlgoMonster and WalkCCC solutions are high-quality and always worth a look.
I haven't checked most of the other solutions, but they might be helpful as well.
And of course, the LeetCode forum is always a good place (or even the best) to look for alternative approaches.
(click on a column header to sort the table)
| author | ||||||||
|---|---|---|---|---|---|---|---|---|
| author | solutions | |||||||
| www | AlgoMonster | C++ | Java | Python | TS | |||
| WalkCCC | C++ | Java | Python | |||||
| leetcode.ca | C++ | Java | Go | Python | Rust | TS | ||
| Progiez | C++ | Java | Python | |||||
| github | charles-wangkai | Java | ||||||
| everthis | JS | |||||||
| fsq | C++ | |||||||
| wisdompeak | C++ | |||||||
| AlgoMonster | C++, Python, Java, TypeScript | |||||||
| WalkCCC | C++, Python, Java | |||||||
| leetcode.ca | C++, Go, Java, Python, Rust, TypeScript | |||||||
| Progiez | C++, Java, Python | |||||||
| charles-wangkai | Java | |||||||
| everthis | JavaScript | |||||||
| fsq | C++ | |||||||
| wisdompeak | C++ |
Videos
Solved On The Same Day
- problem 2929: Distribute Candies Among Children II
- problem 2952: Minimum Number of Coins to be Added
- problem 2975: Maximum Square Area by Removing Fences From a Field
- problem 2959: Number of Possible Sets of Closing Branches
Extra
- Tech Stack - my development environment and tools
- AI - how AI helped me create this website (NOT solving the problems)
- Progress - progression over time
- Quality - code quality